Question:

If Second Saturday and Sunday of every month is a holiday, then the total number of working days in a month of 31 days beginning with a Wednesday will be

Updated On: Jul 15, 2026
  • 23
  • 24
  • 25
  • 26
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The Correct Option is D

Approach Solution - 1

The correct option is (D): 26.
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Approach Solution -2

We need the number of working days in a 31-day month that starts on a Wednesday, where every Sunday and the second Saturday of the month are holidays. Let's list out the calendar day by day and count the holidays directly, then check which option matches.

  1. Option (A): 23: This would mean 8 holidays in the month. Listing the days from Wednesday (day 1) onward, the Sundays fall on days 5, 12, 19 and 26, which is 4 Sundays, and the second Saturday falls on day 11, giving 5 holidays in total, not 8. So 23 is too low.
  2. Option (B): 24: This would need 7 holidays, still more than the 5 holidays actually present in the calendar (4 Sundays plus 1 second Saturday), so this does not match either.
  3. Option (C): 25: This would need exactly 6 holidays. The calendar only gives 5 holidays (days 5, 11, 12, 19, 26), so 25 is one day short of correct.
  4. Option (D): 26: With 4 Sundays (days 5, 12, 19, 26) and 1 second Saturday (day 11) as holidays, that is 5 holidays out of 31 days, leaving 31 minus 5 equals 26 working days. This matches the calendar exactly.

Counting the actual calendar confirms there are 5 holidays and 26 working days.

Therefore, the correct answer is 26.

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Approach Solution -3

The month has 31 days and day 1 falls on a Wednesday. We can assign each day a position in the week using modular arithmetic: counting Wednesday as position 0, Thursday as 1, Friday as 2, Saturday as 3, Sunday as 4, Monday as 5, and Tuesday as 6, the weekday of day \( n \) is given by \( (n - 1) \bmod 7 \). A day is a Sunday when \( (n - 1) \bmod 7 = 4 \), which happens at \( n = 5, 12, 19, 26 \), so there are exactly 4 Sundays. A day is a Saturday when \( (n - 1) \bmod 7 = 3 \), which happens at \( n = 4, 11, 18, 25 \), so the second Saturday falls on \( n = 11 \). That gives \( 4 + 1 = 5 \) holidays, so working days = \( 31 - 5 = 26 \). Let's check each option against this count.

  1. Option (A): 23: This would require 8 holidays in the month, but the congruence \( (n-1) \bmod 7 = 4 \) only has 4 solutions in the range 1 to 31, and only one date satisfies the second-Saturday condition, so 8 holidays is not possible under this calendar.
  2. Option (B): 24: This would require 7 holidays, still more than the 5 dates that actually satisfy the Sunday and second-Saturday congruences worked out above.
  3. Option (C): 25: This would require exactly 6 holidays, one more than the 5 values \( n = 5, 11, 12, 19, 26 \) that the congruences actually produce, so this overcounts by one holiday that does not exist.
  4. Option (D): 26: This matches \( 31 - 5 = 26 \) exactly, using the 5 holiday dates \( n = 5, 11, 12, 19, 26 \) obtained directly from the two modular conditions.

Solving the weekday congruences directly gives exactly 4 Sundays and 1 second Saturday, 5 holidays in total, leaving 26 working days.

Therefore, the correct answer is 26.

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