Question:

If each line of a pair of lines passing through origin is at a perpendicular distance of $4$ units from the point $(3, 4)$, then the equation of the pair of lines is

Updated On: Apr 4, 2024
  • $7x^2 + 24xy = 0$
  • $7y^2 + 24xy = 0$
  • $7y^2 - 24xy = 0$
  • $7x^2 - 24xy = 0$
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The Correct Option is B

Solution and Explanation

Let equation of line passes through origin having slope $m$ is $y-m x=0$, according to given information
$\frac{|4-3 m|}{\sqrt{1+m^{2}}}=4$
$\Rightarrow 16+9 m^{2}-24 m=16+16 m^{2}$
$\Rightarrow 7 m^{2}+24 m=0$
$\Rightarrow m=0$ or $m=-\frac{24}{7}$
so combined equation of required lines
$y\left(y+\frac{24}{7} x\right)=0$
$\Rightarrow 7 y^{2}+24 x y=0$
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Concepts Used:

General Equation of a Line

Equation of Straight Line Formula:

A straight line is a figure created when two points A (x1, y1) and B (x2, y2) are connected with a minimum distance between them, and both the ends are extended to immensity (infinity). With variables x and y, the standard form of a linear equation is: ax + by = c, where a, b, and c are constants and x, and y are variables.

Standard form of a linear equation

Point Slope Form:

The equation of a straight line whose slope is m and passes through a point (x1, y1) is formed or created using the point-slope form. The equation of the point-slope form is:

y - y1 = m (x - x1),

where (x, y) = an arbitrary point on the line.