Question:

If $A$ is a square matrix of order 3 , then | adj $\left(\operatorname{adj} A^{2}\right) \mid$ is equal to

Updated On: Aug 15, 2024
  • $|A |^{2}$
  • $|A|^{4}$
  • $|A|^{8}$
  • $|A|^{16}$
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The Correct Option is C

Solution and Explanation

We know that,
$|\operatorname{adj}(\operatorname{adj} A)| =|A|^{(n-1)^{2}}$
$\left|\operatorname{adj}\left(\operatorname{adj} A^{2}\right)\right| =\left|A^{2}\right|^{(3-1)^{2}} $
$=\left|A^{2}\right|^{2} \,\,[\because n=3] $
$=\left|A^{2}\right|^{4}=|A|^{8}$
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Concepts Used:

Invertible matrices

A matrix for which matrix inversion operation exists, given that it satisfies the requisite conditions is known as an invertible matrix. Any given square matrix A of order n × n is called invertible if and only if there exists, another n × n square matrix B such that, AB = BA = In, where In  is an identity matrix of order n × n.

For example,

It can be observed that the determinant of the following matrices is non-zero.