Question:
How many atoms are there in a unit cell of a diamond lattice (diamond cubic structure)?
How many atoms are there in a unit cell of a diamond lattice (diamond cubic structure)?
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Diamond cubic equals an FCC lattice (4 atoms) plus 4 atoms in tetrahedral voids.
Updated On: Jul 3, 2026
- 2
- 4
- 6
- 8
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The Correct Option is D
Solution and Explanation
Step 1: Diamond cubic = FCC lattice + 2-atom basis.
Step 2: FCC alone gives 4 atoms.
Step 3: 4 more atoms occupy alternate tetrahedral voids.
Step 4: Total=4+4=8.
\[\boxed{Z = 8}\]Was this answer helpful?
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