- Statement I: Transition metals tend to have more stable higher oxidation states as we move down the group due to the increasing availability of d-orbitals. This is in contrast to p-block elements, where higher oxidation states become less stable down the group.
- Statement II: Copper can indeed liberate hydrogen from weak acids such as hydrochloric acid, which is true for copper in the form of copper(I) chloride.
Thus, both statements are true, and the correct answer is (3).
List I | List II |
---|---|
(A) Cr2O72− | (I) +3 |
(B) MnO4− | (II) +5 |
(C) VO3− | (III) +7 |
(D) FeF63− | (IV) +6 |
List-I | List-II | ||
(A) | Oxidation state of Mn in MnO2 is | (I) | +2 |
(B) | Most stable oxidation state of Mn is | (II) | +3 |
(C) | Most stable oxidation state of Mn in \(MnO_{4}^{-}\) is | (III) | +4 |
(D) | Characteristic oxidation state of lanthanoids is | (IV) | +7 |