Question

For spontaneity of a cell, which is correct ?

• A. ΔG = +ve, ΔE = +ve
• B. ΔG = 0, ΔE = 0
• C. ΔG = -ve
• D. ΔG = -ve, ΔE = 0

Answer 1

The Correct Option is C

For spontaneity of a cell, the correct statement is (C) \(ΔG = -ve.\)
The spontaneity of a cell reaction is determined by the Gibbs free energy change \((ΔG)\) of the reaction. 
A negative \( ΔG\) indicates that the reaction is spontaneous, meaning it can occur without the input of external energy. Therefore, for spontaneity, we require \(ΔG\) to be negative.
Option A: \((ΔG = +ve, ΔE = +ve)\) is incorrect because a positive \(ΔG\) and positive \(ΔE\) indicate a non-spontaneous reaction.
Option B: \((ΔG = 0, ΔE = 0)\) is incorrect because a \(ΔG\) of zero indicates that the reaction is at equilibrium, not necessarily spontaneous.
Option D: \((ΔG = -ve, ΔE = 0)\) is incorrect because while a negative \(ΔG\) indicates spontaneity, the value of \(ΔE\) can be non-zero. The cell potential \((ΔE\)\()\) is related to \( ΔG\) through the equation \(ΔG = -nFΔE\), and ΔE can have a non-zero value for spontaneous reactions.
Therefore, the correct statement for spontaneity of a cell is \(ΔG = -ve\), indicating a negative Gibbs free energy change.