C(s)+O2(g)→CO2(g)+400 kJ
C(s)+\(\frac{1}{2}\) O2(g)→CO(s)+100 kJ
When coal of purity 60% is allowed to burn in presence of insufficient oxygen, 60% of carbon is converted into ‘CO’ and the remaining is converted into ‘CO2’. The heat generated when 0.6 kg of coal is burnt is _______.
Weight of coal = 0.6 kg = 600 gm
∴ 60% of it is carbon
So weight of carbon=600×\(\frac{60}{100}\)=360 g
∴ moles of carbon =\(\frac{360}{12}\)=30 moles
C(12 moles)+O2⟶CO2
C(18moles(60% of total carbon)+\(\frac{1}{2}\)O2⟶CO
∴Heat generated =12×400+18×100
=6600 kJ
So, the correct option is (D): 6600 kJ.
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Polluted water may have a value of BOD of the order of 17 ppm.
Reason R: BOD is a measure of oxygen required to oxidise both the bio-degradable and non-biodegradable organic material in water.
In the light of the above statements, choose the most appropriate answer from the options given below.
Oxygen is an important element in the combustion process. It is a member of the chalcogen group on the periodic table which is one of the most abundant elements in the Earth’s crust.
Oxygen is very important for a living organism to survive, multiply, and for converting food into energy. It is the only living gas for human beings and they inhale it from their nose reaching to their lungs.
Only oxygen gas gives our cells the ability to convert food into energy which is very important for us to survive.
Oxygen is a chemical compound with the symbol O and atomic number 8.