The electronic configurations and the number of unpaired electrons for each element are as follows:
Sc: \([ \text{Ar} ] 4s^2 3d^1 \quad (1 \text{ unpaired electron})\)
Cr: \([ \text{Ar} ] 4s^1 3d^5 \quad (6 \text{ unpaired electrons})\)
V: \([ \text{Ar} ] 4s^2 3d^3 \quad (3 \text{ unpaired electrons})\)
Ti: \([ \text{Ar} ] 4s^2 3d^2 \quad (2 \text{ unpaired electrons})\)
Mn: \([ \text{Ar} ] 4s^2 3d^5 \quad (5 \text{ unpaired electrons})\)
Arranging them in increasing order of unpaired electrons, we get:
\(\text{Sc (A)} < \text{Ti (D)} < \text{V (C)} < \text{Mn (E)} < \text{Cr (B)}\)
List-I ( Ions ) | List-II ( No. of unpaired electrons ) | ||
A | Zn$^{2+}$ | (I) | 0 |
B | Cu$^{2+}$ | (II) | 4 |
C | Ni$^{2+}$ | (III) | 1 |
D | Fe$^{2+}$ | (IV) | 2 |
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: