An alkene X on ozonolysis gives a mixture of Propan-2-one and methanal. What is X?
An alkene X on ozonolysis gives a mixture of Propan-2-one and methanal. What is X?
Propene
2-Methylpropene
2-Methylbut-1-ene
2-Methylbut-2-ene
The Correct Option is B
Solution and Explanation
The correct option is: (B): 2-Methylpropene.
The given products of ozonolysis, which are propan-2-one (acetone) and methanal (formaldehyde), provide important clues about the structure of the starting alkene X.
Ozonolysis of an alkene involves breaking the carbon-carbon double bond and forming carbonyl compounds (aldehydes or ketones) as the products. The specific products formed can help us deduce the structure of the alkene.
The reaction can be represented as follows:
Alkene (X) + O₃ (ozone) + Zn, H₂O (reduction) → Carbonyl Compounds
Given that the products are propan-2-one (CH₃COCH₃) and methanal (HCHO), let's analyze how the products relate to the structure of the alkene X.
Propan-2-one (Acetone): The presence of propan-2-one indicates that there must be a branch in the carbon chain of the alkene. This is because acetone has a ketone functional group (C=O) in its structure. The ketone group suggests that the alkene X must have a branch on one of the carbons of the double bond.
Methanal (Formaldehyde): Formaldehyde has an aldehyde functional group (H-C=O). The presence of formaldehyde suggests that the alkene X should have a terminal carbon-carbon double bond (i.e., the double bond should be at the end of the carbon chain).
Based on these observations, we can deduce that the alkene X has a terminal double bond and a methyl group attached to the second carbon from the end of the chain. This is consistent with the structure of 2-methylpropene.
In 2-methylpropene, the carbon-carbon double bond is terminal, and there's a methyl group attached to the second carbon atom. Therefore, the answer, 2-methylpropene, is justified by the presence of the specified products (propan-2-one and methanal) in the ozonolysis reaction, which match the expected products from the structure of 2-methylpropene.
Top Questions on Alkenes
Consider the above reaction and identify the product B.- Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$
Assertion A: Carbon forms two important oxides - $CO$ and $CO _2 .CO$ is neutral whereas $CO _2$ is acidic in nature
Reason R : $CO _2$ can combine with water in a limited way to form carbonic acid, while $CO$ is sparingly soluble in water
In the light of the above statements, choose the most appropriate answer from the options given below - Match List I with List II
List-I
List-II
(A) Cyanocobalamine (I) Hydrogenation of Alkenes (B) Wilkinson catalyst (II) Antipernicious anemia factor (C) D-penicillamine (III) Refining of Ni (D) Mond's Process (IV) Treatment of toxic effects of copper
Choose the correct answer from the options given below: - Find out the major product from the following reaction
- The molality of a $10 \%$ (v/v) solution of di-bromine solution in $CCl _4$ (carbon tetrachloride) is ' $x$ ' $x=$____ $\times 10^{-2} M$ (Nearest integer) [Given : molar mass of $Br _2=160 \,g \,mol ^{-1}$ atomic mass of $C =12\, g \,mol ^{-1}$ atomic mass of $Cl =355\, g\, mol ^{-1}$ density of dibromine $=32 \,g\, cm ^{-3}$ density of $CCl _4=16\, g \,cm ^{-3}$ ]
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Concepts Used:
Alkenes
Alkenes
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
IUPAC Nomenclature of Alkenes
- An alkene or cycloalkene is indicated by the suffix (ending) ene.
- For the root name, the longest chain must include both carbon atoms of the double bond.
- The root chain must be numbered beginning at the end closest to a double bond carbon atom. If the double bond is in the chain's centre, the nearest substituent rule is used to determine where the numbering begins.
- If the compound contains more than one double bond, it is named with a diene, triene, or equivalent prefix indicating the number of double bonds, and each double bond is assigned a locator number.
Read More: Unsaturated Hydrocarbon
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