Question

A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass 𝑚 and radius 𝑟 and it is in a uniform vertical magnetic field \(B_0\), as shown in the figure. Initially, it hangs vertically downwards, because of acceleration due to gravity 𝑔, on two conducting supports at P and Q. When a current 𝐼 is passed through the loop, the loop turns about the line PQ by an angle 𝜃 given by

 

• A. \(tan\theta = \frac{\pi rlB_0}{(𝑚𝑔)}\)
• B. \(tan\theta = \frac{2\pi rlB_0}{(𝑚𝑔)}\)
• C. \(tan\theta = \frac{\pi rlB_0}{(2𝑚𝑔)}\)
• D. \(tan\theta = \frac{mg}{(\pi rlB_0)}\)

Answer 1

The Correct Option is A

The correct option is (A):\(tan\theta = \frac{\pi rlB_0}{(𝑚𝑔)}\)