Question:

A particle connected with light thread is performing vertical circular motion. Speed at point B (Lowermost point) is sufficient, so that it is able to complete its circular motion. Ignoring air friction, find the ratio of kinetic energy at A to that at B. (A being top-most point)
A particle connected with light thread is performing vertical circular motion

Updated On: Feb 6, 2024
  • \(1 : 5\)
  • \(5 : 1\)
  • \(1: 7\sqrt2\)
  • \(1: 5\sqrt2\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The correct option is (A): \(1 : 5\)

Was this answer helpful?
0
0

Top Questions on Uniform Circular Motion

View More Questions

Questions Asked in JEE Main exam

View More Questions

Concepts Used:

Uniform Circular Motion

A circular motion is defined as the movement of a body that follows a circular route. The motion of a body going at a constant speed along a circular path is known as uniform circular motion. The velocity varies while the speed of the body in uniform circular motion remains constant.

Uniform Circular Motion Examples:

  • The motion of electrons around its nucleus.
  • The motion of blades of the windmills.

Uniform Circular Motion Formula:

When the radius of the circular path is R, and the magnitude of the velocity of the object is V. Then, the radial acceleration of the object is:

arad = v2/R

Similarly, this radial acceleration is always perpendicular to the velocity direction. Its SI unit is m2s−2.

The radial acceleration can be mathematically written using the period of the motion i.e. T. This period T is the volume of time taken to complete a revolution. Its unit is measurable in seconds.

When angular velocity changes in a unit of time, it is a radial acceleration.

Angular acceleration indicates the time rate of change of angular velocity and is usually denoted by α and is expressed in radians per second. Moreover, the angular acceleration is constant and does not depend on the time variable as it varies linearly with time. Angular Acceleration is also called Rotational Acceleration.

Angular acceleration is a vector quantity, meaning it has magnitude and direction. The direction of angular acceleration is perpendicular to the plane of rotation.

Formula Of Angular Acceleration

The formula of angular acceleration can be given in three different ways.

α = dωdt

Where,

ω → Angular speed

t → Time

α = d2θdt2

Where,

θ → Angle of rotation

t → Time

Average angular acceleration can be calculated by the formula below. This formula comes in handy when angular acceleration is not constant and changes with time.

αavg = ω2 - ω1t2 - t1

Where,

ω1 → Initial angular speed

ω2 → Final angular speed

t1 → Starting time

t2 → Ending time

Also Read: Angular Motion