Question:

A string of length \(1\text{ m}\) and mass \(490\text{ g}\) is put under a tension of \(25\text{ N}\). A wave of frequency \(120\text{ Hz}\) is sent along it. The speed of this wave is

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For transverse waves on a stretched string, \[ v=\sqrt{\frac{T}{\mu}} \] where \(\mu=\frac{m}{L}\) is the mass per unit length.
Updated On: Jun 25, 2026
  • \(7.14\text{ ms}^{-1}\)
  • \(0.71\text{ ms}^{-1}\)
  • \(0.51\text{ ms}^{-1}\)
  • \(51.0\text{ ms}^{-1}\)
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The Correct Option is A

Solution and Explanation

Step 1: Use the formula for wave speed on a stretched string.
Wave speed on a stretched string is given by \[ v=\sqrt{\frac{T}{\mu}} \] where \[ T=\text{tension in the string} \] and \[ \mu=\text{mass per unit length} \]

Step 2: Calculate linear mass density.
Given: \[ m=490\text{ g}=0.49\text{ kg} \] \[ L=1\text{ m} \] Therefore, \[ \mu=\frac{m}{L} \] \[ \mu=\frac{0.49}{1} \] \[ \mu=0.49\text{ kg m}^{-1} \]

Step 3: Substitute into the wave speed formula.
Given tension: \[ T=25\text{ N} \] Thus, \[ v=\sqrt{\frac{25}{0.49}} \] \[ v=\sqrt{51.02} \] \[ v\approx 7.14\text{ ms}^{-1} \]

Step 4: Final conclusion.
Therefore, the speed of the wave is \[ \boxed{7.14\text{ ms}^{-1}} \]
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