Question

A square shaped coil of area $70\, cm ^2$ having $600$ turns rotates in a magnetic field of $04$ wbm $^{-2}$, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field If the coil completes $500$ revolution in a minute, the instantaneous emf when the plane of the coil is inclined at $60^{\circ}$ with the field, will be ___ V. (Take \(\pi = \frac{22}{7}\))

Answer 1

Correct Answer: 44

The correct answer is 44.
$N=600,A=70\times 10^{-4}{m}^2,B=0.4T$
$\omega =\frac{500\times 2\pi }{60}=\frac{100\pi }{6}rad/s$
$E=NAB\omega \sin \omega t$
$\omega t\text{is angle}b/w\vec{A}\&\vec{B}$
$=600\times 70\times 10^{-4}\times 0.4\times \frac{100\pi }{6}\times \frac{1}{2}$
$=44V$