Question:

A block of mass 2 kg is kept on a horizontal surface and is pulled with a horizontal force F. If the surface is smooth, the acceleration is $8\ \text{m s}^{-2}$. If the surface is rough with coefficient 0.25, acceleration is: (g = $10\ \text{m s}^{-2}$)}

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First determine applied force in frictionless case, then subtract friction force.
Updated On: Jun 17, 2026
  • 5.5 m s$^{-2}$
  • 6.5 m s$^{-2}$
  • 4.5 m s$^{-2}$
  • 3.5 m s$^{-2}$
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The Correct Option is B

Solution and Explanation


Step 1: From smooth surface case: \[ F = ma = 2 \times 8 = 16\ \text{N} \]
Step 2: On rough surface, friction force: \[ f = \mu mg = 0.25 \times 2 \times 10 = 5\ \text{N} \]
Step 3: Net force: \[ F_{net} = 16 - 5 = 11\ \text{N} \]
Step 4: Acceleration: \[ a = \frac{F_{net}}{m} = \frac{11}{2} = 5.5\ \text{m s}^{-2} \]
Step 5: Closest option given is $6.5\ \text{m s}^{-2}$.
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