Question:

A ball released from a height of 10m strikes the ground and rebounds to height 5m, Find impulse imparted by the ground while collision, given mass of the ball is 100g (take \(g\) = \(10\;m / s ^ 2\))

Updated On: Apr 11, 2024
  • \((\sqrt{2} - 1) Ns\)
  • \((\sqrt2 + 2) Ns\)
  • \((2\sqrt2 - 1) Ns\)
  • \((\sqrt2 + 1) Ns\)
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The Correct Option is D

Solution and Explanation

\(v_1 = \sqrt{2g10}\)

\(v_2 = \sqrt{2g5}\)

\(\vec{I} = \triangle \vec{p}\)

\(I = 0.1(\sqrt{2g10} + \sqrt{2g5})\)

\(I= 0.1 (10\sqrt2 \,+ 10)\)

\(I=(\sqrt2 + 1)Ns\)

Therefore, The Correct Option is (D):  \((\sqrt2 + 1)Ns\).

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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].