If xy $\neq$ 0, is $\frac{1}{x} + \frac{1}{y} = 16$?1. x + y = 16xy 2. x = y
If xy $\neq$ 0, is $a > \frac{y}{x}$?1. $a = \frac{1}{x} + \frac{1}{y}$2. x and y are positive integers