y = 3x – 1COLUMN A: xCOLUMN B: \(\frac{y}{3}+3\)
COLUMN A: \(37\times\frac{37}{36}\) COLUMN B: \(37+\frac{37}{36}\)
x and y are positive integers and x > y.COLUMN A: \(\frac{x^2}{y^3}\)COLUMN B: \(\frac{y^3}{x^2}\)
x + 5 = 3 y = 2xCOLUMN A: xCOLUMN B: y
b > 0COLUMN A: a – bCOLUMN B: b – a
Column A:\((\frac{1}{x})^2\)Column B: x2
x >0Column A: \(\frac{1}{x}+\)1Column B: \(\frac{1}{x+1}\)
Equation: \[ x - y - 3 = 0 \]Column A: xColumn B: y
\(x+y+n=15\)\(x+y+k=9\)
\(f(t) = kt\) for all \(t\), where \(k\) is a constant, and \(f(3) = \frac{1}{2}\).
\(m = 4x + 4y\), \(x \neq -y\)
\(x + y = 2\)