The area of an equilateral \( \Delta ABC \) is \( 169\sqrt{3} \text{ cm}^2 \).
Find the in-radius of \( \Delta ABC \).
If
\[ \left(\frac{3}{5}\right)^{3p-2} = \left(\frac{9}{25}\right)^8 \times \left(\frac{3}{5}\right)^{-3} \]
then the value of \( 2p + 1 \) is:
Find the missing character in the given table: