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Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceed the activation energy of second reaction by 20 kJ mol\(^{-1}\). If \(k_1\) and \(k_2\) are the rate constants of first and second reaction respectively at 300 K, then \(\ln \frac{k_{2}}{k_{1}}\) will be___. (nearest integer) [\(R=8.3 \text{ J K}^{-1} \text{ mol}^{-1}\)]
  
  • JEE Main - 2026
  • JEE Main
  • Chemistry
  • Activation energy
Consider the given figure and choose the correct option:
Activation energy
  • JEE Main - 2025
  • JEE Main
  • Chemistry
  • Activation energy

Consider the given figure and choose the correct option:

  • JEE Main - 2025
  • JEE Main
  • Chemistry
  • Activation energy

Consider the following graph between Rate Constant (K) and \( \frac{1}{T} \): Based on the graph, determine the correct order of activation energies \( E_{a1}, E_{a2}, \) and \( E_{a3} \).

  • JEE Main - 2025
  • JEE Main
  • Chemistry
  • Activation energy
The Activation energy for the reaction A $\rightarrow$ B + C, at a temperature $T_K$ was 0.04606 RT J/mol. What is the ratio of Arrhenius factor to the Rate constant for this reaction?
  • COMEDK UGET - 2024
  • COMEDK UGET
  • Chemistry
  • Activation energy