List of top Chemistry Questions on internal energy

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R:
Assertion (A): B_eCl₂ and MgCl₂ produce characteristic flame. 
Reason (R) : The excitation energy is high in B_eCl₂ and MgCl₂ 
In the light of the above statements, choose the correct answer from the option given below

Two moles of an ideal monoatomic gas occupies a volume $V$ at $27^{\circ}C$. The gas expands adiabatically to a volume $2V$. Calculate $(a)$ the final temperature of the gas and $(b) $ change in its internal energy -

One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litres. Then $ {\Delta S (cal \, deg^{-1} \, mol^{-1})}$ for this process is : $ { (R = 2 \, cal \, K^{-1} \, mol^{-1})}$

300 cal of heat is supplied to raise the temperature of 50 g of air from $ 20{}^\circ C $ to $ 30{}^\circ C $ without any change in its volume. Change in internal energy per gram of air is

Internal energy is sum of

Two rigid boxes containing different ideal gases are placed on a table. Box $A$ contains one mole of nitrogen at temperature $T_0$, while box $B$ contains one mole of helium at temperature $(7/3)\, T_0$. The boxes are then put into thermal contact with each other, and heat flows between them until the gases reach a common final temperature (Ignore the heat capacity of boxes). Then, the final temperature of the gases, $T_f$, in terms of/$T_0$ is :

The internal energy of an ideal gas is :

Six moles of an ideal gas performs a cycle shown in figure. If the temperature are $T_A = 600\, K, T_B = 800\, K, T_C = 2200 \,K$ and $T_D = 1200\, K$, the work done per cycle is approximately

One mole of an ideal gas undergoes a cyclic process $ ABCDA $ as shown in the $ P-V $ diagram, Tire net work done in the process is $ (1\, atm = 10^6 $ dyne $ cm^{-2} $ )