A body is projected vertically upwards with a velocity of \( 20~\text{ms}^{-1} \). If the potential energy of the body at a height of \( 5~\text{m} \) from the ground is \( 100~\text{J} \), then the kinetic energy of the body at a height of \( 10~\text{m} \) from the ground is
\textit{(Acceleration due to gravity \( g = 10~\text{ms}^{-2} \))}