List of top Chemistry Questions on Some basic concepts of chemistry asked in WBJEE


The correct option for the above reaction is 
A metal $M$ (specific heat $0.16$) forms a metal chloride with $= 65\%$ chlorine present in it. The formula of the metal chloride will be
How many moles of electron weight one kilogram :
In a flask, the weight ratio of $CH _{4}( g )$ and $SO _{2}(g)$ at $298 \,K$ and 1 bar is $1: 2$. The ratio of the number of molecules of $SO _{2}(g)$ and $CH _{4}(g)$ is
The weight of oxalic acid that will be required to prepare a $1000\, mL$ $\left(\frac{N}{20}\right)$ solution is
Equal weights of $CH_{4}$ and $H_{2}$ are mixed in an empty container at $25^\circ C$. The fraction of the total pressure exerted by $H_{2}$ is
$2\,gm$ of metal carbonate is neutralized completely by $100 \,mL$ of $0.1 \,(N) \,HCl$. The equivalent weight of metal carbonate is
The amount of the heat released when $20\,mL$ $0.5\, M\, NaOH$ is mixed with $100\, mL\, 0.1\, M\, HCl$ is $x\, kJ$. The heat of neutralization is
The molarity of a $NaOH$ solution by dissolving $4 \,g$ of it in $250\, ml$ water is
In the reaction of sodium thiosulphate with $I_2$ in aqueous medium, the equivalent weight of sodium thiosulphate is equal to
An organic compound made of $C, H$ and $N$ contains $20\%$ nitrogen. Its molecular weight is :
$2N HCl$ solution will have same molar concentration as a
Sodium nitrate on reduction with $Zn$ in presence of $NaOH$ solution produces $NH_3$ Mass of sodium nitrate absorbing $1$ mole of electron will be
An unknown element forms an oxide. What will be the equivalent weight of the element if the oxygen content is $20\%$ by weight?
$1$ mole of methyl amine on reaction with nitrous acid gives at $NTP$
If molecular weight of $ KMn{{O}_{4}} $ is $M$, then its equivalent weight in acidic medium would be
The energy of electron in 1st orbit of Hydrogen atom is –2.18 × 10-18 Joule. The third ionisation energy of Li+2 ion is
The following graph shows how T1/2(half-life) of a reactant R changes with the initial reactant concentration a0.
The order of the reaction will be :