List of top Mathematics Questions on Quadratic Equations asked in UP Board X

Sum of the areas of two squares is $157 \, m^2$. If the sum of their perimeters is 68 meters, then find the sides of both squares.
If one root of the quadratic equation $x^2 + 3x - p = 0$ is 2, then find the value of $p$.
Find two consecutive odd positive integers, sum of whose squares is 290.
The discriminant of the quadratic equation $ax^2 + bx + c = 0$ will be:
If the roots of the quadratic equation $3x^2 - 12x + m = 0$ are equal, then the value of $m$ will be:
Find two consecutive positive integers whose sum of squares is 365.
Sum of two numbers is 8 and sum of their inverses is \( \frac{8}{15} \). Find the numbers.
Find the roots of the quadratic equation \( \sqrt{3}x^2 - 11x + 8\sqrt{3} = 0 \).
Find the roots of the quadratic equation \( 4x^2 + 3x + 5 = 0 \).
The roots of the equation \( x^2 - 2x + 1 = 0 \) will be:
If one root of the equation \( x^2 + kx - 6 = 0 \) is -2, then the value of \( k \) will be:
Discriminant of the quadratic equation \( 3x^2 - 6x + 4 = 0 \) will be:
If roots of the equation \( 3x^2 - 12x + k = 0 \) are equal, then the value of \( k \) will be:
If one root of the equation \( x^2 - 4x + k = 0 \) is 6, then the value of \( k \) will be:
Find the discriminant of the quadratic equation \( 2x^2 - 4x + 3 = 0 \) and then find the nature of the roots.
The discriminant of the equation $3x^2 - 2x + \frac{1}{3} = 0$, will be:
If one root of the equation $2x^2 + ax + 6 = 0$ is 2, then the value of $a$ will be:
The roots of equation \( 4x^2 - 12x + 9 = 0 \) will be:
If the roots of the quadratic equation $3x^2 - 12x + m = 0$ are equal, the value of $m$ will be:
The sum of the roots of the equation \( 5x^2 - 3x + 2 = 0 \) will be:
The roots of the quadratic equation $x^2 - 3x - 10 = 0$ are:
Find the discriminant of the quadratic equation \( 4x^2 - 6x + 5 = 0 \) and hence find the nature of its roots.
If the roots of the quadratic equation \( ax^2 + bx + c = 0 \) are equal, then the value of \( c \) is:
Find the roots of the equation \( x + \frac{1}{x} = 3, \, x \neq 0 \).
Find two consecutive positive integers, the sum of whose squares is 365.