If \( \Delta_r = \begin{vmatrix} 1 & 2 & r\\ 3r-2 & 3r-5 & 2 \\ 0 & 3 & 3r+1 \end{vmatrix} \) (inferred), then \( \sum_{r=1}^{33} \Delta_r' = \)
(Note: Based on the answer options, the question implies a telescoping sum resulting in 0.99, likely \( \sum \frac{3}{(3r-2)(3r+1)} \).)