If \[ z = \frac{(2-i)(1+i)^3}{(1-i)^2} \] then \[ \text{Arg}(z) = ? \]
If \( \sqrt{5} - i\sqrt{15} = r(\cos\theta + i\sin\theta), -\pi < \theta < \pi, \) then
\[ r^2(\sec\theta + 3\csc^2\theta) = \]
If Xn = cos \(\frac{ π}{2^n}\) + i sin\(\frac{ π}{2^n}\) , then
If the roots of the equation z2 - i = 0 are α and β, then | Arg β - Arg α | =
The locus of z such that \(\frac{|z-i|}{|z+i|}\)= 2, where z = x+iy. is