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Why is $ F_2 $ the strongest oxidizing agent (among halogens) although electron affinity of $ Cl_2 $ is higher than $ F_2 $ ?
Why is $ F_2 $ the strongest oxidizing agent (among halogens) although electron affinity of $ Cl_2 $ is higher than $ F_2 $ ?
Updated On: Jun 6, 2024
- Low enthalpy of dissociation and high free energy of hydration
- Low enthalpy of dissociation
- High free energy of hydration
- High electronegativity and low free energy of hydration
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The Correct Option is A
Solution and Explanation
$F_{2}$ is strongest oxidising agent due to its low enthalpy of dissociation as $F?F$ bond is weak and high enthalpy of hydration of small $F^{-}$ ion
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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