Concept:
Divisibility rules allow us to check if an integer can evenly divide a target number without performing full long division.
• Rule for 9: An integer is divisible by 9 if and only if the sum of its individual digits is perfectly divisible by 9.
• Rule for 11: An integer is divisible by 11 if the absolute difference between the sum of the digits at odd positions and the sum of the digits at even positions is either 0 or a multiple of 11.
• Rule for 8: A number is divisible by 8 if its last three digits form a number divisible by 8.
• Rule for 14: A number is divisible by 14 if it is simultaneously even (divisible by 2) and divisible by 7.
Step 1: Test the rule of divisibility for 9 on the value 454545.
Let us compute the sum of all digits making up the given integer:
\[
\text{Sum of digits} = 4 + 5 + 4 + 5 + 4 + 5
\]
Group the identical digits together:
\[
\text{Sum of digits} = (4 \times 3) + (5 \times 3) = 12 + 15 = 27
\]
Now evaluate if this sum is divisible by 9:
\[
27 \div 9 = 3
\]
Since the sum of the digits (27) is a multiple of 9, the entire number 454545 must be completely divisible by 9. Let us check this explicitly:
\[
454545 \div 9 = 50505
\]
The remainder is exactly 0, confirming absolute divisibility.
Step 2: Cross-verify other options to confirm exclusivity.
• Testing 11:
\[
\text{Sum of odd position digits } (1^{\text{st}}, 3^{\text{rd}}, 5^{\text{th}}) = 4 + 4 + 4 = 12
\]
\[
\text{Sum of even position digits } (2^{\text{nd}}, 4^{\text{th}}, 6^{\text{th}}) = 5 + 5 + 5 = 15
\]
\[
\text{Difference} = |12 - 15| = 3
\]
Since 3 is not a multiple of 11, the number is not divisible by 11.
• Testing 8 and 14: The given integer 454545 is an odd number (it ends in 5). Therefore, it cannot be divided completely by any even number, automatically ruling out 8 and 14.
Thus, Option (C) is the only correct answer.