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Question:
Which one of the following mono-enes does not exhibit geometric isomerism?
Which one of the following mono-enes does not exhibit geometric isomerism?
Updated On: May 15, 2024
- $C_{4}H_{8}$
- $C_{3}H_{6}$
- $C_{5}H_{10}$
- $C_{8}H_{16}$
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The Correct Option is B
Solution and Explanation
The main conditions for exhibiting geometrical isomerism are
(i) presence of double bond.
(ii) presence of different groups on same double bonded carbon.
(iii) presence of at least one similar group on adjacent double bonded carbon atoms.
$\therefore C_{3} H_{6}\left(\stackrel{3}{C} H_{3}-\stackrel{2}{C} H=\stackrel{1}{C} H_{2}\right)$
does not exhibit geometric isomerism due to presence of same group on double bonded carbon atom $\left(C_{1}\right)$.
(i) presence of double bond.
(ii) presence of different groups on same double bonded carbon.
(iii) presence of at least one similar group on adjacent double bonded carbon atoms.
$\therefore C_{3} H_{6}\left(\stackrel{3}{C} H_{3}-\stackrel{2}{C} H=\stackrel{1}{C} H_{2}\right)$
does not exhibit geometric isomerism due to presence of same group on double bonded carbon atom $\left(C_{1}\right)$.
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Concepts Used:
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Hydrocarbons can be described as organic compounds that consists only hydrogen and carbon atoms. These compounds are of different types and thereby have distinct natures. Hydrocarbons are colorless gases and are known for discharging faint odours. These have been categorized under four major classes named as alkynes, alkanes, alkenes, and aromatic hydrocarbons.
Types of Hydrocarbons
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