To determine which statements about Zn, Cd, and Hg are correct, let's evaluate each option provided:
Considering the evaluation:
Therefore, the correct answer is: B, D only.
- (A) Incorrect. Zn, Cd, and Hg exhibit lower enthalpy of atomization compared to other transition metals in their respective series because they have fully filled d-subshells, which make their bonding weaker.
- (B) Correct. Zn and Cd do not show variable oxidation states, generally remaining in the \( +2 \) state. Hg, however, can show \( +1 \) and \( +2 \) oxidation states due to its unique electron configuration.
- (C) Incorrect. Compounds of Zn, Cd, and Hg are typically diamagnetic because they have fully filled d-orbitals, which do not contribute to unpaired electrons.
- (D) Correct. Zn, Cd, and Hg are known as soft metals due to their malleability and ductility.
The Correct Answer is: B, D only
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,