Which of the following statement is incorrect?
- Low solubility of LiF in water is due to its small hydration enthalpy.
- \(KO _2\) is paramagnetic.
- Solution of sodium in liquid ammonia is conducting in nature.
- Sodium metal has higher density than
The Correct Option is A
Solution and Explanation
The low solubility of LiF in water is not primarily due to its small hydration enthalpy. Instead, it is primarily due to the strong ionic interaction between lithium and fluoride ions, which makes it difficult for water molecules to break apart the crystal lattice and solvate the ions.
So, the correct option is (A): Low solubility of LiF in water is due to its small hydration enthalpy.
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Reasons R: The deep blue solution to the formation of amide.
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B. The reducing ability of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
C. Among the hydrides, \(\text{NH}_3\) is a strong reducing agent while \(\text{BiH}_3\) is a mild reducing agent.
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Concepts Used:
Group 1 Elements
Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.
Alkali metals are characterized by one s-electron in the valence shell of their atoms.
Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:
- Lithium(Li)
- Sodium(Na)
- Potassium (K)
- Rubidium (Ru)
- Cesium (Cs)
- Francium (Fr)
They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.
Electronic Configuration:
- Alkali metals have one electron in their valence shell.
- The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
- They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).
This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.
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