To determine which solution has the highest depression in freezing point, we need to consider the colligative properties of solutions, specifically the freezing point depression.
Colligative Properties: Freezing point depression is given by the formula:
ΔTf = i · Kf · m
where ΔTf is the depression in freezing point, i is the van 't Hoff factor (number of particles the solute breaks into), Kf is the cryoscopic constant of the solvent, and m is the molality of the solution.
Analyzing Each Option:
Conclusion: Given that acetic acid has a higher molar mass than glucose and ionizes in water, it will result in a greater freezing point depression.
Thus, the solution with the highest depression in freezing point is: 180 g of acetic acid dissolved in water.
To determine which solution has the highest depression in freezing point or lowest freezing point, we need to consider the concept of colligative properties, specifically the depression of freezing point.
Depression in Freezing Point:
The depression in freezing point (\(ΔT_f\)) is given by the formula:
\(ΔT_f = i \cdot K_f \cdot m\)
The greater the number of particles (\(i \cdot m\)), the greater the depression of freezing point, and consequently, the lower the freezing point of the solution.
Evaluation of Options:
Considering the dissociation and ionization:
Conclusion: The solution with 180 g of acetic acid dissolved in water exhibits the highest depression in freezing point due to its ability to ionize, leading to the lowest freezing point.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| Sample | Van't Haff Factor |
|---|---|
| Sample - 1 (0.1 M) | \(i_1\) |
| Sample - 2 (0.01 M) | \(i_2\) |
| Sample - 3 (0.001 M) | \(i_2\) |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: