



The Freundlich adsorption isotherm is an empirical relationship that describes the adsorption of gases or solutes onto a surface. It is represented by: \[ \frac{x}{m} = k p^{1/n} \] where $x$ is the mass of the adsorbate, $m$ is the mass of the adsorbent, $p$ is the pressure, and $k$ and $n$ are constants. The graphical representations are:
A: Correct, shows $\frac{x}{m}$ vs $p$ with a logarithmic relationship.
B: Correct, shows $\log \frac{x}{m}$ vs $\log p$ as a straight line.
D: Correct, shows a logarithmic relationship $\frac{x}{m}$ vs $p^{1/n}$.
C: Incorrect, as it shows a constant $\frac{x}{m}$, not related to Freundlich's isotherm. \end{itemize}
Thus, the correct representations are A, B, and D.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
One mole of an ideal monoatomic gas is subjected to changes as shown in the graph The magnitude of the work done (by the system or on the system) is _______ J (nearest integer)
Given : \(\log 2=0.3 \ln 10=2.3\)
In figure, a straight line is given for Freundrich Adsorption\((y=3 x+2505)\) The value of \(\frac{1}{ n }\)and\(\log K\)are respectively
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,