Question:
Which of the following reaction/s will not give \(p-\) aminoazobenzene?
Which of the following reaction/s will not give \(p-\) aminoazobenzene?
Updated On: Apr 19, 2026
- $A$ only
- $B $ only
- $C$ only
- $A$ and $B$
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The Correct Option is B
Solution and Explanation
To determine which reactions will not give \(p-\)aminoazobenzene, let's analyze each option:
- Option A:
- The starting compound is nitrobenzene.
- Step (i) reduces nitrobenzene to aniline using \(\text{Sn/HCl}\)
- .
- Step (ii) forms a diazonium salt with \(\text{HNO}_2\).
- Step (iii) involves coupling with aniline, forming \(p-\)aminoazobenzene.
- Option B:
- The starting compound is nitrobenzene.
- Step (i) attempts reduction using \(\text{NaBH}_4\), which does not reduce nitrobenzene effectively to form aniline.
- Because the reduction is ineffective, further steps are rendered irrelevant for forming \(p-\)aminoazobenzene.
- Option C:
- The starting compound is aniline.
- Step (i) forms a diazonium salt with \(\text{HNO}_2\).
- Step (ii) involves coupling with aniline, forming \(p-\)aminoazobenzene.
Based on the analysis, only Option B will not give \(p-\)aminoazobenzene.
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Concepts Used:
Preparation of Amines
- Reduction of nitro compounds: Nitro compounds are reduced to amines by reduction with metals in an acidic medium or by passing them through hydrogen gas in the presence of finely divided nickel, palladium, or platinum.
- Ammonolysis of alkyl halides: Alkyl benzyl halide undergoes a nucleophilic substitution reaction while reacting with an ethanolic solution of ammonia where the halogen atom is replaced by an amino group and this process of splitting of the C-X bond by an ammonia molecule is called ammonolysis.
- Reduction of Nitriles: On reduction of nitriles with lithium or aluminum hydride or catalytic hydrogenation are used.
- Reduction of amides: On reduction, the amides with lithium aluminum hydride yield amines.
- Gabriel phthalimide synthesis: Gabriel synthesis is used to prepare primary amines. Phthalimidewhen treated with ethanolic potassium hydroxide, forms potassium salt of phthalimide which when heated with alkyl halide followed by alkaline hydrolysis leads to the formation of the corresponding primary amine.
- Hoffmann bromamide degradation reaction: In the Hoffmann bromamide degradation reaction, the transfer of an alkyl or aryl group takes place from the carbonyl carbon of the amide to the nitrogen atom. The amine so formed, therefore, contains one carbon less than that present in the initial amine.