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Which of the following orders regarding ionization energy is correct ?
Which of the following orders regarding ionization energy is correct ?
Updated On: Apr 27, 2024
- $N > O > F$
- $N < O < F$
- $N > O < F$
- $N < O > F$
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The Correct Option is C
Solution and Explanation
Ionisation energy is the energy required to remove an electron from outer shell of an atom. Since, on moving from left to right in a period, size decreases, thus, larger amount of energy is required to remove an electron, ie, ionisation energy increases.
Although the size of $O$ atom is smaller as compared to $N$ but the ionisation energy of $N$ is higher. This is because in case of $N$, the electron is to be removed from half-filled $2 p^{3}$ orbital. Thus, the order of ionisation energy is
$O < N < F$
Although the size of $O$ atom is smaller as compared to $N$ but the ionisation energy of $N$ is higher. This is because in case of $N$, the electron is to be removed from half-filled $2 p^{3}$ orbital. Thus, the order of ionisation energy is
$O < N < F$
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Concepts Used:
Haloalkanes and Haloarenes - Classification
Classification of Haloalkanes and Haloarenes are as follows:
Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:
These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;
- Monohaloalkane
- Dihaloalkane
- Trihaloalkane
Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)
This class includes:
- Alkyl halides or haloalkanes (R—X)
- Allylic halides
- Benzylic halides
Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond
This class includes:
- Vinylic halides
- Aryl halides
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