An ambidentate ligand is a ligand that can bind to a central metal ion through two different donor atoms.
\(C2O_4^{2-}\) (Oxalate): Oxalate is a bidentate ligand, meaning it binds through two oxygen atoms. However, both oxygen atoms are equivalent, so it is not ambidentate. It always binds through its two oxygen atoms.
\(SCN^-\)(Thiocyanate): Thiocyanate can bind through either the sulphur atom (thiocyanate-S) or the nitrogen atom (thiocyanate-N), making it ambidentate.
\(NO_2^-\) (Nitrite): Nitrite can bind through either the nitrogen atom (nitro) or the oxygen atom (nitrate), making it ambidentate.
\(CN^-\)(Cyanide): Cyanide can bind through either the carbon atom (cyano) or the nitrogen atom (isocyanate), making it ambidentate. Although cyanide preferentially binds through carbon, the possibility of N-bonding makes it technically ambidentate.
(A) [FeO4]2− (B) [Fe(CN)6]3−
(C) [Fe(CN)5NO]2− (D) [CoCl4]2−
(E) [Co(H2O)3F3]
Choose the correct answer from the options given below :
Match List - I with List - II:
List - I:
(A) \([ \text{MnBr}_4]^{2-}\)
(B) \([ \text{FeF}_6]^{3-}\)
(C) \([ \text{Co(C}_2\text{O}_4)_3]^{3-}\)
(D) \([ \text{Ni(CO)}_4]\)
List - II:
(I) d²sp³ diamagnetic
(II) sp²d² paramagnetic
(III) sp³ diamagnetic
(IV) sp³ paramagnetic
Match the LIST-I with LIST-II
Choose the correct answer from the options given below:
Given below are two statements:
Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism
Statement II: cis- and trans-platin are heteroleptic complexes of Pd.
In the light of the above statements, choose the correct answer from the options given below
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.