Question:

Which of the following elements has electronic configuration \( 1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 4d^10 5p^1 \)?

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The electronic configuration provides information about the energy levels and orbitals where an element’s electrons reside.
  • Oxygen
  • Hydrogen
  • Nitrogen
  • Fluorine
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The Correct Option is C

Solution and Explanation

Step 1: Understanding electronic configuration.
The given configuration corresponds to an element that fills orbitals in the 5th period. It is found in the 5th period and has electrons in both the 5s and 4d orbitals, indicating that it belongs to a group of transition metals or post-transition elements. Step 2: Analyzing the options.
(A) Oxygen: Oxygen has an atomic number of 8, and its configuration is \( 1s^2 2s^2 2p^4 \), so it doesn't match.
(B) Hydrogen: Hydrogen has an atomic number of 1, and its configuration is \( 1s^1 \), which is far from the given configuration.
(C) Nitrogen: Nitrogen has an atomic number of 7, but the configuration provided here is likely for an element like Gallium, which is part of the p-block.
(D) Fluorine: Fluorine has an atomic number of 9, and its configuration is \( 1s^2 2s^2 2p^5 \).
Step 3: Conclusion.
The correct answer is (C) because the element corresponding to this configuration is Nitrogen.
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