Which of the following displaces $Br _{2}$ from an aqueous solution containing bromide ions?
- $ Cl^{-} $
- $ Cl_{2} $
- $I _{3}^{-}$
- $ I_{2} $
The Correct Option is B
Solution and Explanation
ie, $ F _{2}> Cl _{2}> Br _{2}> I _{2}$.
So, $Cl _{2}$ will displace $Br ^{-}$and $I ^{-}$ions from their solutions.
$Cl _{2}+2 Br ^{-} \longrightarrow Br _{2}+2 Cl ^{-} .$
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Concepts Used:
Group 17 Elements
Halogens are the group 17 elements of the periodic table. The term ‘halogen’ means ‘salt-producing’, hence the name halogens as they possess the tendency to form salts after reacting to metals. It generally has five elements:
- Fluorine (F)
- Chlorine (Cl)
- Bromine (Br)
- Iodine (I)
- Astatine (At)
These are all naturally occurring halogens but Tennessine (Ts) is an artificially created halogen.
Halogens:
Halogens are highly reactive elements and are highly electronegative. They have a high tendency to react with metals to form salts. They are also known as Group 17 elements. They have 7 electrons in their outer shell with a configuration of (ns2 np5). Fluorine being the first halogen in group 17, is highly reactive. Astatine is a halogen because of its resemblance with iodine despite it being radioactive.
Electronic Configuration:
The general electronic configuration for group 17 elements is ns2np5. This configuration clearly shows that they have 7 electrons in their valence shell. They require one more electron to complete their octet and achieve noble gas configuration.
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