Question:

Which of the following amines has lowest \(pK_b\) value?

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A lower \(pK_b\) means a stronger base.
Updated On: Jun 16, 2026
  • \(C_6H_5-N(CH_3)_2\)
  • \(C_6H_5-NH(CH_3)\)
  • \(C_6H_5-NH_2\)
  • [structure (D) - image pending]
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The Correct Option is A

Solution and Explanation

Concept:
A lower \(pK_b\) means a stronger base. Among aromatic amines, replacing the N-H hydrogens with electron-donating alkyl (\(-CH_3\)) groups increases the electron density on nitrogen, making the lone pair more available and the amine more basic.

Step 1:
Compare the substitution on nitrogen: aniline \(C_6H_5NH_2\) has no methyl, N-methylaniline \(C_6H_5NH(CH_3)\) has one methyl, and N,N-dimethylaniline \(C_6H_5N(CH_3)_2\) has two methyl groups donating electron density to N.

Step 2:
More alkyl groups means greater +I (electron donating) effect and stronger base. So basic strength order is \(C_6H_5N(CH_3)_2 > C_6H_5NH(CH_3) > C_6H_5NH_2\). The strongest base has the lowest \(pK_b\).

Answer: Option (1) — \(C_6H_5-N(CH_3)_2\) is the most basic and so has the lowest \(pK_b\) value.
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