Question:

Which has minimum bond angle?

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Drago's rule is a powerful shortcut. When the central atom is from the 3rd period or lower (like P, S, As, Se) and is bonded to a less electronegative atom like Hydrogen, assume no hybridization. The bond angles will be very close to $90^\circ$, making them smaller than any comparable $sp^3$ hybridized molecule from the 2nd period.
Updated On: Apr 21, 2026
  • $\text{NH}_3$
  • $\text{H}_2\text{O}$
  • $\text{PH}_3$
  • $\text{H}_2\text{S}$
  • $\text{SO}_2$
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Use VSEPR Theory
Bond angle depends on:
• Number of lone pairs
• Hybridization
• Repulsion: lp-lp > lp-bp > bp-bp

Step 2: Analyze Each Molecule

(A) NH3
sp3 with 1 lone pair ⇒ 107°

(B) H2O
sp3 with 2 lone pairs ⇒ 104.5°

(E) SO2
sp2 with 1 lone pair ⇒ ≈ 119°

(C) PH3
Due to weak hybridization (Drago’s rule):
Bond angle ≈ 93.5°

(D) H2S
Less hybridization + 2 lone pairs ⇒ ≈ 92°

Step 3: Compare Values
SO2 > NH3 > H2O > PH3 > H2S

Step 4: Final Answer
H2S
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