When light travels from a rarer medium to a denser medium, its speed decreases. Since the frequency of light remains constant when it enters a new medium, its wavelength decreases.
The relationship between the speed \( v \), frequency \( f \), and wavelength \( \lambda \) is given by: \[ v = f \lambda \]
Since the frequency remains constant and the speed decreases in a denser medium, the wavelength must decrease.
Hence, the correct answer is (D).
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = 4/3 \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \frac{n_2}{2n_1} \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is cm. 