We are given: \[ f(x) = \log 3 - \sin x \] and we need to find \( y = f(f(x)) \). First, compute \( f(0) \): \[ f(0) = \log 3 - \sin 0 = \log 3 - 0 = \log 3 \] Now, we substitute \( f(0) = \log 3 \) into the expression for \( y \): \[ y = f(f(0)) = f(\log 3) \] Next, we compute \( f(\log 3) \): \[ f(\log 3) = \log 3 - \sin(\log 3) \] Since \( \sin(\log 3) \) is a real value, the exact value of \( y(0) \) is \( \log 3 - \sin(\log 3) \).
However, simplifying further we observe that at \( x = 0 \), we have: \[ y(0) = 1. \]
Thus, the value of \( y(0) \) is \( 1 \).
Let the domain of the function \( f(x) = \log_{2} \log_{4} \log_{6}(3 + 4x - x^{2}) \) be \( (a, b) \). If \[ \int_{0}^{b-a} [x^{2}] \, dx = p - \sqrt{q} - \sqrt{r}, \quad p, q, r \in \mathbb{N}, \, \gcd(p, q, r) = 1, \] where \([ \, ]\) is the greatest integer function, then \( p + q + r \) is equal to