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Question:
When the same amount of zinc is treated separately with
excess of sulphuric acid and excess of sodium hydroxide, the
ratio of volumes of hydrogen evolved is
When the same amount of zinc is treated separately with
excess of sulphuric acid and excess of sodium hydroxide, the
ratio of volumes of hydrogen evolved is
Updated On: Jun 23, 2023
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The Correct Option is A
Solution and Explanation
The balanced chemical reaction of zinc with sulphuric acid and
NaOH are
Zn + $H_2SO_4 \, \rightarrow \, ZnSO_4 + H2(g) \uparrow$
$ Zn + 2NaOH + 2H_2O \rightarrow Na_2[Zn(OH)_4] + H_2 (g) \uparrow$
Since, one mole of$ H_2(g)$ is produced per mole of zinc with both
sulphuric acid and NaOH respectively, hydrogen gas is produced in
the molar ratio of 1:1 in the above reactions.
NaOH are
Zn + $H_2SO_4 \, \rightarrow \, ZnSO_4 + H2(g) \uparrow$
$ Zn + 2NaOH + 2H_2O \rightarrow Na_2[Zn(OH)_4] + H_2 (g) \uparrow$
Since, one mole of$ H_2(g)$ is produced per mole of zinc with both
sulphuric acid and NaOH respectively, hydrogen gas is produced in
the molar ratio of 1:1 in the above reactions.
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(B) Chemical Classification:
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