When a current of $2\,A$ flows in a battery from negative to positive terminal, the potential difference across it is $12 \,V$. If a current of $3\,A$ flowing in the opposite direction produces a potential difference of $15\, V$, the emf of the battery is
Let $\varepsilon$ be emf and $r$ be internal resistance of the battery.
In first case,
$12 = \varepsilon - 2r \quad ...(i)$
In second case,
$15 = \varepsilon + 3r \quad...(ii)$
Subtract $(i)$ from $(ii)$, we get
$r = \frac{3}{5} \Omega$
Putting this value of $r$ in eqn. $(i)$, we get
$\varepsilon = 12 + \frac{2\times 3}{5} $$ = \frac{60+6}{5}$$= \frac{66}{5} = 13.2\,V$
A device that converts chemical energy into electrical energy is called an electric cell. To an electric circuit, the battery provides the constant electromotive force.
Each cell comprises 2 half cells which are connected in series by a conductive electrolyte containing anions and cations:
One-half cell is made up of electrolyte and a negative electrode called an anion.
The other half cell is made up of electrolytes and a positive electrode called a cathode.
Redox reactions take place simultaneously.
While charging, cations are reduced at the cathode, and anions are oxidized at the anode.
Electrodes do not join each other as they are electrically connected by the electrolyte.