Question:

What is the moment of inertia of solid sphere of density $\rho$ and radius $R$ about its diameter?

Updated On: Aug 1, 2022
  • $\frac{105}{176} R^{5}\,\rho$
  • $\frac{105}{176} R^{2}\,\rho$
  • $\frac{176}{105} R^{5}\,\rho$
  • $\frac{176}{105} R^{2}\,\rho$
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The Correct Option is C

Solution and Explanation

Moment of inertia of solid sphere of mass $M$, density $\rho$ and radius $R$ about its diameter is $I=\frac{2}{5}MR^{2}=\frac{2}{5}\left(\frac{4}{3}\pi R^{3}\rho\right)R^{2}$ $=\frac{8}{15}\pi R^{5}\rho=\frac{8}{15}\times\frac{22}{7}\pi R^{5}\rho$ $=\frac{176}{105}R^{5}\rho$
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.