18g
9g
The molar mass of water (H$_2$O) is calculated as: \[ \text{Molar mass of H}_2\text{O} = (2 \times 1) + (16) = 18 \, \text{g/mol} \] Now, we calculate the mass of 0.5 moles of water: \[ \text{Mass} = \text{Moles} \times \text{Molar mass} = 0.5 \, \text{mol} \times 18 \, \text{g/mol} = 9 \, \text{g} \] Thus, the mass of 0.5 moles of water is 9 g. So, the correct answer is option (2).
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
X g of nitrobenzene on nitration gave 4.2 g of m-dinitrobenzene. X =_____ g. (nearest integer) [Given : molar mass (in g mol\(^{-1}\)) C : 12, H : 1, O : 16, N : 14]