Question:

Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that 'O' is their common point for the two. The wires carry I1 and I2 currents, respectively. Point 'P' is lying at distance 'd' from 'O' along a direction perpendicular to the plane containing the wires. The magnetic field at the point 'P' will be:

Updated On: May 22, 2024
  • \(\frac{\mu_o}{2\pi d}(I_1+I_2)\)
  • \(\frac{\mu_o}{2\pi d}(I_1^2+I_2^2)\)
  • \(\frac{\mu_o}{2\pi d}(I_1^2+I_2^2)^{\frac{1}{2}}\)
  • \(\frac{\mu_o}{2\pi d}(\frac{I_1}{I_2})\)
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The Correct Option is C

Solution and Explanation

The correct option (C): \(\frac{\mu_o}{2\pi d}(I_1^2+I_2^2)^{\frac{1}{2}}\)
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