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Question:
To send 10% of main current through a moving coil galvanometer of resistance $99\,\Omega$ the shunt
required is
To send 10% of main current through a moving coil galvanometer of resistance $99\,\Omega$ the shunt
required is
Updated On: May 27, 2022
- $9\,\Omega$
- $11\,\Omega$
- $10\,\Omega$
- $9.9\,\Omega$
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The Correct Option is B
Solution and Explanation
105 = G + S $i.e.$ 9S = G = 99 $i.e.$ S = 11
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- For a current carrying loop having N turns, and cross sectional area A, carrying current i, whenever it is placed in and along the direction of an external magnetic field B, it experiences a torque given by:
ԏ = NiAB
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