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The work done by the force \(\overrightarrow F = (x^2-y^2)\hat{i} + (x+y)\hat{j}\) in moving a particle along the closed path C containing the curves x + y = 0, x2+ y2 = 16 and y = x in the first and fourth quadrant is
The work done by the force \(\overrightarrow F = (x^2-y^2)\hat{i} + (x+y)\hat{j}\) in moving a particle along the closed path C containing the curves x + y = 0, x2+ y2 = 16 and y = x in the first and fourth quadrant is
Updated On: Sep 29, 2024
- \(\frac{52}{3}\)units
- 52π+94units
- 52π-96units
- 96π-52units
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The Correct Option is C
Solution and Explanation
The correct answer is(C): 52π-96units
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