Question:

The speed of earth?s rotation about its axis is $\omega$. Its speed is increased to $x$ times to make the effective acceleration due to gravity equal to zero at the equator. Then $x$ is

Updated On: Sep 23, 2024
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The Correct Option is C

Solution and Explanation

Earth rotates about its own axis in 24 h.
So, T = 24 x 60 x 60 s
So, angular speed of earth about its own axis
$\omega=\frac{2\pi}{T}=\frac{2\pi}{24\times60\times60}rad s^{-1}$
At equator, $g' = g - R_e\omega'^2$
or $=g - R_e\omega'^2$
or $\omega'=\sqrt{\frac{g}R_e}=\frac{2\pi}{84.6\times60}$
= $\frac{\omega'}{\omega}=\frac{24\times60\times60}{84.6\times60}=17$
$\Rightarrow \omega'=17\omega$
So, value of x is 17.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].