Question

The resistivity of a $0.8 M$ solution of an electrolyte is $5 \times 10^{-3} \Omega cm$ Its molar conductivity is ____ $\times 10^4\, \Omega^{-1}\, cm ^2 \,mol ^{-1}$

Answer 1

Correct Answer: 25

${\Lambda }_m=\frac{\kappa \times 1000}{M}$
${\Lambda }_m=\frac{1}{\rho }\times \frac{1000}{M}$
$\frac{1}{5\times 10^{-3}}\times \frac{1000}{0.8}$
So , correct answer is $25\times 10^4{\Omega }^{-1}c{m}^{-2}mo{l}^{-1}$